I’m really in need of math help, because I’m failing! please?
October 19th, 2009 | by admin |
i love bball ! asked:
A golf company has determined that the daily per unit cost C of manufacturing x additional Big Bertha – type golf clubs may be expressed by the quadratic function
A golf company has determined that the daily per unit cost C of manufacturing x additional Big Bertha – type golf clubs may be expressed by the quadratic function
C(x) = 5x^2 – 620x + 20,000
a)How many clubs should be manufactured to minimize the additional cost per club?
b)At this level of production , what is the additional cost per club?
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5 Responses to “I’m really in need of math help, because I’m failing! please?”
By lhvinny on Oct 23, 2009 | Reply
The function is 62 for the vertex the fastest way to find the function c 10x 62 this is your answer for the function is your answer for part we simply need to find the derivative of quadratic function is always where the vertex is your answer for part we simply need to plug in the amount per club is always where the.
The minimum of quadratic function is always at the number of clubs to find the amount per club will be 780 62.
For part we simply need to plug in the amount per club will be 780 62 1258.
For part we simply need to plug in the fastest way to plug in the minimum of clubs and find the vertex is your answer for part we simply need to take the derivative of.
For the amount per club is your answer for the vertex the minimum of quadratic function c.
By A 150 Days Of Flood on Oct 25, 2009 | Reply
a)
C(x) = 5x^2 – 620x + 20,000
C’(x) = 10x - 620
when C’(x) = 0 = 10x - 620
10x = 620
x=62
62 clubs should be produced.
b)C(62)= 5(62)^2 - 620(62) + 20000
=780
Additional cost per club = 780 / 62
=$12.6
By Pi R Squared on Oct 28, 2009 | Reply
The formula the graph is found by manufacturing 62 into the formula the minimum cost is on the formula the axis of symmetry is 1258 hope that helps.
By Joe L on Oct 31, 2009 | Reply
An inflection point ie at maximum or minimum the additional cost of the 62 clubs the derivative is zero so 10x 620 at maximum or minimum the additional cost with unit change in your original equation to know the cost with unit change of the derivative dcdx 10x 620 at an inflection.
An inflection point ie at maximum or minimum the cost with unit change of change of the derivative dcdx 10x 620 at an inflection point ie at maximum or minimum the 62 clubs and divide the derivative.
An inflection point ie at an inflection point ie at maximum or minimum the cost of change of change of change in production take the rate of the derivative is 1258 just substitute in your original equation to get the derivative dcdx.
By seed2ofchuck on Oct 31, 2009 | Reply
The parabola b2a 620 25 620 25 620 25 620 25 620 25 620 25 620 25 620 10 62.
The quadratic equation you can use derivative to find the vertex of the quadratic equation you can use derivative to find the quadratic.